a boy is moving on a straight road against a frictional force of 5N, after travelling a distance of 1.5km ,he forget the correct path at a round about of radius 100m. however, he moves on the circular path for one and half cycle and then he moves forward up-to 2.0 km. calculate the work done by him.
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18.5 kilojoule
force acting= 5N
total disolacement = 3700m ( 1500 + 200 + 2000)
workdone = force * displacement
= 5 * 3700
= 18500 j
=18.5 kj
force acting= 5N
total disolacement = 3700m ( 1500 + 200 + 2000)
workdone = force * displacement
= 5 * 3700
= 18500 j
=18.5 kj
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7
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nice NE................
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