Question

a boy is pulling a load of 150 with a string inclined at an angle of 30 to the horizontal.if the tension in the string is 150 ,the force tending to lift the load off the ground is?

Answer 1

The force will have two components one is 150sin 30°=75N(vertical force )
and one is 150cos 30°=75√3N(horizontal force)
So 75√3N is carrying it forward and 75N is carrying it upward from the ground.
Therefore correct answer is 75N.

Answer 2

Answer: If f(t)=2t3+9t2+at-b where a and b are constant,find the values of the

constant a and b Hence

(1) factorize f(t) completely

(2) State the zeros of f(t)

(3) find the remainder when f(t) is divided by (t-5)