A boy is pushing a 60 kg box along the floor by applying a horizontal force of 150 N. The box is accelerating at a rate of 0.5 m/s2.
What is the net force on the box? Round your answer to the nearest whole number.
What is the magnitude of the force of friction acting on the box? Round your answer to the nearest whole number.
What is the coefficient of kinetic friction (μk) between the floor and the box? Round your answer to two decimal places.
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Explanation:
- According to second law of motion F=ma but in these case friction is working opposite to the force of boy's force .So the current acceleration is the result of friction.We can calculate the net force by Subtracting the actual force (150)by friction force. That would be 150 N =60. x .the value of X will be 2.5m/s but the acceleration is 0.5m/s.So force applied by Friction will be 2.5-0.5 . 60=120N
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