A boy is running along the sides of a rectangular farm of sides 30 m and 40 m as shown in fig. If he starts from point A with a uniform speed of 5 m/s in direction ABCD then what is the value of distance and displacement after 14 seconds ?
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11th
Physics
Motion in a Straight Line
Distance and Displacement
A boy starts towards the ea...
PHYSICS
A boy starts towards the east with a uniform speed 5m/s. After t=2 second he turns right and travels 40 m with same speed. Again he turns right and travels for 8 second with the same speed. Find out the displacement, average speed, average velocity, and total distance traveled.
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ANSWER
REF.Image.
Distance covered in 25=v.t=10m v=5m/s
85=v.t=40m
His path :
Taking A are origin
A≡(0,.0)
D=(−30,−40)
(t=
v
d
=
5
40
=8s)
(1)Displacement =d(AD)=
40
2
+30
2
=
1600+900
=
2500
=
50m
(ii) Total distance =10+40+40=
90m
(iii) Avg. speed =
TotalTime
TotalDistance
=
2+8+8
90m
=
18
90
=
5m/s
(iv)Avg. velocity =
Totaltime
TotalDisplacement
=
18
50
=
2.78m/s
in
AD
direction
Explanation:
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