a boy is running at a speed of p km/h to cover a distance of 1km. but due to the slippery ground, his speed is reduced by q km/h. if he takes 'r' hours to cover the same distance, then ?
1. 1/r = pq/ p + q
2. 1/r = p + q
3. 1/r = p-q
4. r = p-q
Answers
Answered by
6
I think something is missing here,
total times taking by him during = r hrs
let t1 time take to cover 1 km with speed P km/h
then , t1 = 1/P
and t2 time taken to cover 1 km with speed q km/h
then,
t2 = 1/q
now , total time = r
then ,
1/P + 1/q = r
r = (P +q )/Pq
1/r = Pq/(P + q)
hence option (1) is correct ,
total times taking by him during = r hrs
let t1 time take to cover 1 km with speed P km/h
then , t1 = 1/P
and t2 time taken to cover 1 km with speed q km/h
then,
t2 = 1/q
now , total time = r
then ,
1/P + 1/q = r
r = (P +q )/Pq
1/r = Pq/(P + q)
hence option (1) is correct ,
Answered by
4
Answer:
C
Step-by-step explanation: old speed is p km/h
so new speed will be = p - q km/h
distance = 1 km
total time = r hours
so by formula : time = distance / speed
r = 1 / p - q
OR
1 / r = p - q
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