Physics, asked by divyansh123456789, 10 months ago

A boy is running on a straight road.He runs 500m towards north in 2minutes 10seconds and then turns back and runs 200m in 1.00 minute.Calculate his average speed and magnitude of average velocity during first 2minutes 10seconds and his average speed and magnitude of average velocity during the whole journey.​

Answers

Answered by PramodAcharya
1

Answer:

For first half of journey till t=2mins10secs=130secs,

distance=displacement=500m

speed=

speed=

         =3.84m/sec       

velocity=

 velocity=  

           =3.84m/sec  towards north

For whole journey, when t=3mins 10 secs= 190secs

distance=(500+200)m=700m

displacement=(500-200)m=300m towards north

speed=

         =

         =3.78m/sec

velocity=

           =

           =1.57m/sec towards north

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