A boy is running on a straight road.He runs 500m towards north in 2minutes 10seconds and then turns back and runs 200m in 1.00 minute.Calculate his average speed and magnitude of average velocity during first 2minutes 10seconds and his average speed and magnitude of average velocity during the whole journey.
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Answer:
For first half of journey till t=2mins10secs=130secs,
distance=displacement=500m
speed=
speed=
=3.84m/sec
velocity=
velocity=
=3.84m/sec towards north
For whole journey, when t=3mins 10 secs= 190secs
distance=(500+200)m=700m
displacement=(500-200)m=300m towards north
speed=
=
=3.78m/sec
velocity=
=
=1.57m/sec towards north
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