A boy is running on a straight road. He runs 500m towards North in 2 minutes 10 seconds
and then turns back and runs 200m in 1 minute. Calculate: (a) his average speed and
magnitude of average velocity during first 2minutes 10 seconds. (b) his average speed
and magnitude of average velocity during the whole journey.
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Answer:
Explanation:
Let the boy start from a point A and B point is 500 m away from it .
And a C point which is 200 m away from point B .
Now
Time taken to reach at point B.
T= 130s
Distance = 500m
avg speed = 500/ 130
= 3.7m/s
displacement = 500m
v.avg = 500 / 130
= 50 / 13
= 3.7 m/s
Total joutney's avg speed
= (500/ 130 + 200 / 60 ) / 2
= ( 3.7 + 3.3 ) / 2
= 7 / 2
= 3. 5 m/s
as we know the AC = 300m
And time taken from reaching A to C is
= 130 - 60 sec
= 70 sec
Total avg velocity
= 300 / 70
= 4.2 m/s
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