Question

a boy is running with a uniform speed of 5m/s to catch a bus standing on the road ahead of him. when the boy is 12m behind the bus, the bus starts moving with a constant acceleration of 1m/s^2. when does the boy catch the bus ? what distance is covered by the bus during the time ​

Answer 1

Answer:

.. A boy who is 48m behind the bus starts running at 10m/s. After what time will the boy able to catch the bus? ... In this time, bus moves a distance of ( 10t - 48) m. ( 10t ...

Answer 2

Answer:

it's answer is 4 second and 8 m.

when the boy came to point a bus started to move from point c let the boy catch the bus after 30 second at the point d.

then distance covered by the boy is 5t

sboy=5t

is covered by the bus is t square upon 2

sbus=t²/2 subtracting equation two from 1 we get

sboy-sbus=5t-t²/2

12×2=10t-t²

on solving this we get

t =4 and 6

now you can find other required answer