Question

A boy is sitting on a horizontal platform of a joy wheel at a distance of 5m from the center. The wheel begins to rotate and when the angular speed exceeds 1 rad/s, the boy just slips. The coefficient of friction between the boy and the wheel is

Answer 1

Dear student, friction must greater for without slipping

Answer 2

Answer:

$\mu=0.51$

Explanation:

It is given that,

A boy is sitting on a horizontal platform of a joy wheel at a distance of 5 m from the center, r = 5 m

When the angular speed exceeds 1 rad/s, the boy just slips, $\omega=1\ rad/s$

The condition for which the boy does not slips is :

$f\ge mr\omega^2$

f is frictional force

$\mu N\ge mr\omega^2$

$\mu mg= mr\omega^2$

$\mu=\dfrac{r\omega^2}{g}$

$\mu=\dfrac{5\times 1^2}{9.8}$

$\mu=0.51$

So, the coefficient of friction between the boy and the wheel is 0.51. Hence, this is the required solution.