Question

a boy is standing at a circular ground about 8m away from the road the road is 12m long and lies across the circular ground How much distance will the boy have to walk to reach to the extreme point of the road ?​

Answer 1

The boy has to walk 10 m.

Step-by-step explanation:

See the attached diagram.

A is the position of the boy, O is the center of the ground and B is one extreme point of the road.

Given that a boy is standing at a circular ground about 8 m away from the road.

Assume that the boy is at 8 m perpendicular distance from the center of the road which is 12 m long and lies across the circular ground.

Now, the distance of the extreme point of the road from the center is 6 m.

And hence, the boy has to cover a distance of $\sqrt{8^{2} + 6^{2}} = 10$ m to reach one extreme point of the road. (Answer)