A boy is standing at the centre of a boat which is free to move on water. If the masses of the boy and the boat
are m, and m, respectively and the boy moves a distance of 1m forward then the movement of the boat is
metres
m2
m1
m2
mi
[21 m₂ + m2
[31 m2
mi
[1 m, + m2
Answers
Answer:
Explanation:
=> Here,
mass of boy = m₁
momentum of boy = m₁v₁
mass of boat = m₂
momentum of boy + boat = (m₁ + m₂)v
time of travel = t
the movement of the boat along with boy, L = ?
=> According to the law of conservation of momentum,
Momentum of the boy = Momentum of boy + momentum of boat
m₁v₁ = m₁v + m₂v
m₁v₁ = (m₁ + m₂)v
but, v = L/t
m₁L₁/t = (m₁+m₂)L/t
m₁*1/t = (m₁+m₂)L/t
m₁*t/t = (m₁+m₂)L
L = m₁ / (m₁ + m₂)
Thus, the movement of the boat along with the boy is m₁ / (m₁ + m₂).
Answer:mass of boy = m₁
momentum of boy = m₁v₁
mass of boat = m₂
momentum of boy + boat = (m₁ + m₂)v
time of travel = t
the movement of the boat along with boy, L = ?
=According to the law of conservation of momentum,
Momentum of the boy = Momentum of boy + momentum of boat
m₁v₁ = m₁v + m₂v
m₁v₁ = (m₁ + m₂)v
but, v = L/t
m₁L₁/t = (m₁+m₂)L/t
m₁×1/t = (m₁+m₂)L/t
m₁×t/t = (m₁+m₂)L
L = m₁ / (m₁ + m₂) Ans...
HOPE it helps you...
Mark it as brainliest...
Follow me...
Explanation: