A boy is standing on the ground and flying a kite with 100m of string at an elevation of 30. Another boy is standing on the roof of a 10m high building and is flying his kite at an elevation of 45. Both the boys are on opposite sides of both the kites. Find the length of the string that the second boy must have so that the two kites meet.
Answers
Step-by-step explanation:
The height of the first kite above ground = 100 m * Sin 30 = 50 meters
The height of the first kite above ground = 100 m * Sin 30 = 50 metersLet the length of the second kite be : L meters
The height of the first kite above ground = 100 m * Sin 30 = 50 metersLet the length of the second kite be : L metersHeight of 2nd kite: L Sin 45 + 10 meters
The height of the first kite above ground = 100 m * Sin 30 = 50 metersLet the length of the second kite be : L metersHeight of 2nd kite: L Sin 45 + 10 meters So L sin 45 + 10 = 50 m
The height of the first kite above ground = 100 m * Sin 30 = 50 metersLet the length of the second kite be : L metersHeight of 2nd kite: L Sin 45 + 10 meters So L sin 45 + 10 = 50 m => L = 40√2 meters of the string that that the second boy must have so that the two kites meet.Hope this would be helpful.
Answer:
Height of 1 kite is 100 m
Height of 2 kite is 50 m.
Height of string is 40√2 m