A boy is twice as his brother. Five years hence the product of their ages is 375. Find their present ages
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AnswEr :
A boy is twice as his brother. Five years hence the product of their ages is 375.
Their present ages.
Let the present age of brother be r
Let the present age of boy be 2r
We know that negative value isn't acceptable.
Thus,
Given :-
- Boy is Twice as old as his Brother.
- Five years hence the product of their ages is 375.
Solution :-
Lets Assume That, His brother Present age is = x years.
Than, Boy Present age = 2 * x = 2x years.
A/q,
→ After 5 years His brother will be = (x + 5) years old.
→ Boy will be = (2x + 5) years old.
So,
→ (x + 5) * (2x + 5) = 375
→ 2x² + 5x + 10x + 25 = 375
→ 2x² + 15x + 25 - 375 = 0
→ 2x² + 15x - 350 = 0
Splitting The Middle Term now,
→ 2x² - 20x + 35x - 350 = 0
→ 2x(x - 10) + 35(x - 10) = 0
→ (x - 10)(2x + 35) = 0
Putting both Equal to Zero now,
→ x - 10 = 0
→ x = 10
Or,
→ 2x + 35 = 0
→ 2x = (-35)
→ x = (-35/2) ≠ Negative Value of age Not Possible.
Hence,
→ His Brother Present Age = x years = 10 years.
→ And, Boy Present Age = 2x years = 2*10 = 20 years.