Question

A boy is walking along boundary of a circular park of diameter 140 m. He completes one round of this park. Find the distance and displacement covered by that boy.​

Answer 1

Answer:

Displacement is the shortest distance possible between initial and final position.

As the athlete is in circular motion , displacement is zero. [ THis is because , the initial and final position is the same ]

Distance covered in 1 round = Circumference of the circle

Circumference of the circle = 2πr

Diameter = 200 m

Radius = 100 m

Distance covered in 1 round[ 40 sec ] = 2 × 22/7 × 100 = 628.57 m

Distance covered in 1 sec = 628.57 ÷ 40 = 15.71 m

2min 20 sec = 140 sec

Distance covered in 140 sec = 15.71 × 140 = 2199.4 m

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Answer 2

Answer:

distance=440 m

displacement=0

Explanation:

As the athlete is in circular motion , displacement is zero. [ This is because , the initial and final position is the same ]

Distance covered in 1 round = Circumference of the circle

Circumference of the circle = 2πr

Diameter = 140 m

Radius = 70 m

$2 \times \pi \times r \\ = (2 \times \frac{22}{7} \times 70)m \\ = 440m$