Question

a boy is whirling 20g stone in a horizontal circle by tying it to one end of the string of length 2.0.if the stone is making 4 revolutions in 1 second then assuming the other end of the string stationary calculate the tension produced on the string,

Answer 1

Answer:

25.24N

Explanation:

Refer to the material.

Answer 2

ANSWER:

Tension produced on the string is F=25.24 N

EXPLANATION:

The time taken to complete 4 Revolution is one second  

The weight of the stone attached to the string is 20 grams  

The length of the string to which the stone is attached is 2 cm  

Before finding the tension letters find the angular velocity of the stone  

$w=r e v \times 2 \pi$

$w=8 \pi$

When the stone is rotated a centripetal force is acted inside the circular motion and centrifugal force is acting outside the circular motion of the stone, hence the tension on the wire due to the rotation of the stone is

$F=r w^{2} m$

$F=(8 \pi)^{2}\left(\frac{20}{1000}\right)^{2}$

F=25.24 N