Math, asked by resham2, 1 year ago

A boy is 'x' years old and 5 years hence his age will be half that of his father . how old is the father now

Answers

Answered by Fuschia
2
Present age of boy = x

After 5 years his age = x + 5

A/Q ---
x + 5 = 1/2 of father's age
2(x + 5) = father's age

Present age of father = 2(x + 5) - 5 = 2x + 10 - 5
= 2x + 5 years

Hope This Helps You!

resham2: still confused with the last part of the ans
Answered by ROYALJATT
1
Let
The present age of father = y 
The father's age after 5 years = p

We know that -
Present age of boy = x
Age of boy after 5 years = x + 5
 
Now Acc to question 
Age of boy after 5 years = half of father's age after 5 years
x + 5 = 1/2 * p
2(x + 5) = p

So the present age of father i given as 
y = p - 5
y = 2(x + 5) - 5
y = 2x+10-5
y = 2x + 5 (REQUIRED ANSWER)

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Best of luck ;)
ROYALJATT
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