A boy is x years old. His father is five times as old as he is. If the difference in their ages is 32 years,
(a) form an equation in x,
(b) solve the equation to find the boy's age.
Answers
Answered by
1
Answer:
The son is now 10 years old.
Let,the son is X years old
So the father is 5X years old
We can write, after 10 years
(X+10)+(5X+10)=80
6X+20=80
6X=60
X=10
which is the son’s age
Answered by
2
Answer:
(a) As the father is five times older than he is, and the difference in their ages is 32, it can be represented by the following equation:-
5x-x=32
(b) In the equation- 5x-x=32
4x=32
x=32/4=8
Therefore the age of the boy is 8
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