Question

A boy jumps 2 meter on the surface of earth.What distance will he cover on the surface of moon where g is 1/6th of the value of Earth?

Answer 1

$\huge\red{\underline{{\boxed{\textbf{QUESTION}}}}}$

A boy jumps 2 meter on the surface of earth.What distance will he cover on the surface of moon where g is 1/6th of the value of Earth?

$\huge\red{\underline{{\boxed{\textbf{ANSWER}}}}}$

We have

g moon=1/6 of g earth

g moon=10/6

On the earth

g=10 m/s^2. H= 2 m

We know that.

v=√2gh

v=√2×10×2

v=√40 m/s

And v=u. Because (v=√2gh.

V=√2gu^2/2g. V=u)

So u= √40m/s

And on the moon

h=u^2/2g

h=(√40)^2/2×10/6

h= 40×6/20

h=240/ 20

Height or distance = 12 m

@HarshPratapSingh

Answer 2

Answer:

We have

g moon=1/6 of g earth

g moon=10/6

On the earth

g=10 m/s^2. H= 2 m

We know that.

v=√2gh

v=√2×10×2

v=√40 m/s

And v=u. Because (v=√2gh.

V=√2gu^2/2g. V=u)

So u= √40m/s

And on the moon

h=u^2/2g

h=(√40)^2/2×10/6

h= 40×6/20

h=240/ 20

Height or distance = 12 m