A boy jumps a distance of 2m on the surface of the earth. What distance will he jump on the surface of the moon where g is 1/6th of the value on the surface of the earth?
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Solution :-
Assuming that the boy's leg muscles apply exactly the same force as on Earth, the maximum distance of the jump will be around 12 m on the surface of the Moon because Moon's gravity is 1/6th of Earth's gravity. The absence of air is one factor. Also, the leg muscles will not have the usual pull of Earth's gravity acting on them. In my opinion, this will improve the jumping ability. So, jumping will be much more easier on the Moon.
So, the distance of boy's jump will be around 12 m.
Assuming that the boy's leg muscles apply exactly the same force as on Earth, the maximum distance of the jump will be around 12 m on the surface of the Moon because Moon's gravity is 1/6th of Earth's gravity. The absence of air is one factor. Also, the leg muscles will not have the usual pull of Earth's gravity acting on them. In my opinion, this will improve the jumping ability. So, jumping will be much more easier on the Moon.
So, the distance of boy's jump will be around 12 m.
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Answer:
so using
where
g= acceleration due to gravity
s= total height
and v=0
then we get
for earth
So using
we get
h=12 m
so the boy can jump height of 12 m on moon's surface
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