A boy jumps from a wall 3m high. What is an estimate of the change in momentum of the boy when he lands without rebounding?
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Velocity of boy with which it hits the ground is
v = √(2gH)
= √(2 × 10 m/s^2 × 3 m)
= √(60) m/s
Boy is doesn’t rebounds.
So,
change in momentum = mv - 0
= Mass of boy × √(60) m/s
Mass of boy is not given. Can’t proceed further.
v = √(2gH)
= √(2 × 10 m/s^2 × 3 m)
= √(60) m/s
Boy is doesn’t rebounds.
So,
change in momentum = mv - 0
= Mass of boy × √(60) m/s
Mass of boy is not given. Can’t proceed further.
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