Question

A boy leaves his home at 8:45 a.m. and walks to school 1.25 km away. He arrives at school at
9:20 a.m. What is his average speed?​

Answer 1

Answer:

Average Speed is a quantity that defines the speed which is the mean of all the speeds traveled during your journey. In terms of Formula, we can write it as,

$\implies \text{Average Speed} = \dfrac{\text{Total Distance Traveled}}{\text{Total Time Taken}}$

According to the question,

• Total Distance traveled = 1.25 km = 1250 m
• Total Time Taken = 35 minutes = 2100 seconds

Calculating the speed, we get it as:

$\implies \text{Average Speed} = \dfrac{1250}{2100} \dfrac{m}{s}\\\\\implies \text{Average Speed} = \boxed{0.59\: m/s}$

Hence the Average Speed of the boy is 0.59 m/s

Answer 2

$\LARGE\underline{\underline{\sf \red{Given}:}}$

• Boy leaves his home at 8:45am and arrives of school at 9:20am

• Distance travelled by boy is 1.25km

$\LARGE\underline{\underline{\sf \red{To\:Find}:}}$

• Average Speed of boy = ?

$\LARGE\underline{\underline{\sf \red{Solution}:}}$

Time of travelling (t) = 8:45am to 9:20am

$\implies{\sf 35\:mins }$

We know that :

${\boxed{\sf Average\:Speed=\frac{Total\:Distance}{Total\:Time} }}$

In meter/min :-

Distance = 1.25km = 1250m

$\implies{\sf Speed=\dfrac{1250}{35} }$

$\implies{\sf Speed=35.71m/min}$

In m/sec :

Time = 35 min = 2100s

$\implies{\sf Speed=\dfrac{1250}{2100} }$

$\implies{\sf Speed =0.59m/s}$

In km/hr :

Time = 35min

$\implies{\sf \dfrac{35}{60} }$

$\implies{\sf 0.583hours}$

$\implies{\sf Speed=\dfrac{1.25}{0.583}}$

$\implies{\sf Speed = 2.14km/hr}$

$\LARGE\underline{\underline{\sf \red{Answer}:}}$

•°• Average speed of student is

35.71 m/min or 0.59m/s or 2.14km/hr