A boy leaves his house at 9:00 AM for his school. The school is 5 km away. He returns home at 3 PM. What is his displacement and distance at 3 PM.
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Your Question:-
A boy leaves his house at 9:00 AM for his school. The school is 5 km away. He returns home at 3 PM. What is his displacement and distance at 3 PM.
Your Answer:
since he goes to school
Distance ⇒ 5 km
Displacement ⇒ 0 as he comes back to his home from school.
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Exact Question:-
A boy leaves his house at 9.30AM for his school. The school is 2 Km away and classes start at 10.00 Am. If he walks at a speed of 3 Km/hr for the first Km at what speed should he walk the second Km to reach just in time?
Exact Answer:-
Distance = 2 km
Total time = 30 min = 0.5 hour
Initial speed = 3km/h for first 1 km
Hence time taken = distance/speed = 1/3 h
Time left = 0.5 - 1/3 = 0.5/3 h
Distance left = 1 km
Hence speed at which he should walk the second km would be
1/(0.5/3) = 6 km/h
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