Question

A boy leaves his house at 9:00 AM for his school. The school is 5 km away. He returns home at 3 PM. What is his displacement and distance at 3 PM.
please answer me​

Answer 1

Your Question:-

A boy leaves his house at 9:00 AM for his school. The school is 5 km away. He returns home at 3 PM. What is his displacement and distance at 3 PM.

Your Answer:

since he goes to school

Distance ⇒ 5 km

Displacement ⇒ 0 as he comes back to his home from school.

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Exact Question:-

A boy leaves his house at 9.30AM for his school. The school is 2 Km away and classes start at 10.00 Am. If he walks at a speed of 3 Km/hr for the first Km at what speed should he walk the second Km to reach just in time?

Exact Answer:-

Distance = 2 km  

Total time = 30 min = 0.5 hour

Initial speed = 3km/h for first 1 km

Hence time taken = distance/speed = 1/3 h  

Time left = 0.5 - 1/3 = 0.5/3 h

Distance left = 1 km

Hence speed at which he should walk the second km would be

1/(0.5/3) = 6 km/h

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