a boy leaves his house at 9:30 a.m. for the school the school is 2 kilometre away and the classes starts at 10:00 a.m. if he walks at the speed of 3 kilometre per hour for the first kilometre at what speed should he walk second kilometre to reach just in time
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Answer:
He should walk the second kilometre in speed = 6km/hr to reach just in time.
Explanation:
The total distance = 2 kilometer
Speed of the boy for the first kilometer
= 3 km/hr
Hence the time taken by him to cover the first kilometer distance .:
t = distance / speed
=> t = (1/3) hr = 60/3 = 20 minutes
Thus the time left to cover the remaining one kilometer = total time available - time already consumed
=> time left in minutes = 30 - 20= 10
Hence the speed required to reach school at time = 1km/10min....(eq.1)
= 1000m/10min = 100meter/minute
In meter per second
= 100/60 = 10/6 = 1.67 m/s
In kilometer per hour
speed = 1km/10min (from eq.1)
= 1÷1/6 km/hr
which equals to 1×6/1 = 6km/hr
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