Question

a boy lifted his 40 kg body at 0.25 meters in 2 seconds.what is the power used. please ans with process

Answer 1

power is equals to work done by time period
work is equals to mass times displacement therefore 40 into 0.25 equals to 10 joule
therefore power is equals to work done divided by time taken that is 10 / 2 which is equals to 5 watt

Answer 2

$\huge{\mathfrak{\blue{AnswEr}}}$

given=> m = 40kg,

h =0.25 m

t =2s..

to find= power...

we have,,,

power, P = $\frac{W}{t}$

= $\frac{mgh}{t}$

= $\frac{40 × 0.25× 9.8}{2}$

= $\frac{98}{2}$

= 49 watt or 49kg$m^{2}$ $\frac{1}{s}$

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