Physics, asked by singhvikas4166, 9 months ago

A boy move 6m north 8m east and 10m verticullyupward what is the ruesltent displacement for initalposition

Answers

Answered by nirman95
37

A boy most 6 metres towards north then moves 8 metres towards east and finally 10 metres vertically upwards.

We have to find out the resultant displacement from the initial position.

Let's define displacement :

Displacement is the shortest length between the starting and the stopping point. Its a vector having both magnitude and direction.

Calculation:

Since all the directions are mutually perpendicular to one another so we can find out displacement as follows :

d =  \sqrt{ {(6)}^{2} +  {(8)}^{2}   +  {(10)}^{2} }

 =  > d =  \sqrt{ 100 + 100 }

 =  > d =  \sqrt{ 200 }

 =  > d = 10 \sqrt{2}  \: m

So final answer will be :

Displacement is 10√2 m.

Answered by AdorableMe
37

GIVEN :-

A boy move 6 m north 8 m east and 10 m vertically upwards.

TO FIND :-

The resultant displacement from the initial position.

PRE-REQUISITE :-

Displacement is the shortest length between the initial position and the final position.

OR

Displacement is the change in position vector.

SOLUTION :-

If a body moves 6 m North, 8 m East and 10 m vertically upwards then its resultant displacement from initial position will be in the form of a cuboid with length 6 m,  breadth 8 m and height 10 m.

And the resultant displacement would be the diagonal of this cuboid.

So, the diagonal of a cuboid :-

√(6²+8²+10²)

= √200

= √(100 × 2)

= 10√2

∴ So, the displacement of the boy from his initial position is 10√2 units.

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