A boy moves along the path ABCD. What is the total distance covered by the boy? What is his net displacement? 50 m D B C A 20
anandimenon:
Please make the question clear... Anyways guessing the question to be as i've thought, here goes the answer...Pls see below..
Answers
Answered by
10
Let us assume this path to be a rectangle ABCD.
AB=CD=50 m BC=DA=20 m T
otal distance is the total distance actually covered by him.
So Total Distance = 50+20+50+ 20
Total Distance = 140m
Net displacement is the distance between the initial and the final position.
Since in this case the initial and final position is the same, the displacement is zero.
AB=CD=50 m BC=DA=20 m T
otal distance is the total distance actually covered by him.
So Total Distance = 50+20+50+ 20
Total Distance = 140m
Net displacement is the distance between the initial and the final position.
Since in this case the initial and final position is the same, the displacement is zero.
Answered by
2
Answer:
Explanation:
Let us assume this path to be a rectangle ABCD.
AB=CD=50 m BC=DA=20 m T
otal distance is the total distance actually covered by him.
So Total Distance = 50+20+50+ 20
Total Distance = 140m
Net displacement is the distance between the initial and the final position.
Since in this case the initial and final position is the s
Similar questions