A boy moves on the track as shown below. He travels with a constant speed of
0.5 m/s during his journey from A to B and B to P. The magnitude of his average
velocity for the trip from Ato Pis [Given AB=BQ=6m and PQ=3m)
Answers
Given:
Boy travels with a constant speed of 0.5 m/s during his journey from A to B and B to P.
To find:
The magnitude of his average velocity for the trip from A to P is
Solution:
From given, we have the data as follows.
Boy travels with a constant speed of 0.5 m/s during his journey from A to B and B to P.
AB = BQ = 6m and PQ = 3m
The journey of boy from A to Q can be given as follows.
A B P Q
Firstly, we will compute the time taken by the boy to complete his journey.
We know the formula for calculating the speed.
Speed = Distance / Time
0.5 m/s = (AB + BQ) / t
0.5 = (6 + 6) / t
0.5 = 12 / t
t = 12 / 0.5
Therefore, the time taken is 24 s.
The average velocity of a boy can be calculated as follows.
v_{avg} = (AB + BQ - PQ) / t
v_{avg} = (6 + 6 - 3) / 24
v_{avg} = 9 / 24
v_{avg} = 0.375 m/s
Therefore, the magnitude of boy's journey is 0.375 m/s.