Question

a boy moves with a velocity of 2 metre per second for 5 second he then the accelerates uniformly for the next five second to attain a velocity of 10 metre per second he then so down at uniform rate to stop in the next 10 second plot a velocity time graph on this information find the distance travelled by a body in last 10 second calculate his acceleration from t=5 second to t=10 second. (plz answer me soon) ​

Answer 1

Explanation:

The initial velocity is

u=0ms−1

The acceleration is

a=10m

s−2

The time is

t=5s

Apply the equation of motion

v=u+at

The velocity is

v=0+10⋅5=50ms−1

The distance travelled in the first

5s

is

s=ut+12at2

=0⋅5+12⋅10⋅52=125m

The distance travelled in the following

10s is

s1=vt 1250⋅10=500m

The total distance travelled is

d=s+s1=125+500=625m