Question

a boy moving by a bike with the velocity 4 m/ s accelerate for 6 sec . at the rate of 2 m / s . find its final velocity​

Answer 1

$\bigstar$ Given

A boy moving by a bike with the velocity 4 m/s accelerate for 6 sec at the rate of 2 m/s²

$\bigstar$ To Find

Final velocity

$\bigstar$ Solution

We know that

Equation of motion

$\sf \longrightarrow v=u+at$

Here

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• t = Time

Units

• v = m/s
• u = m/s
• a = m/s²
• t = s

According to the question

We are asked to find final velocity

Therefore

We must find "v"

Given that

A boy moving by a bike with the velocity 4 m/s accelerate for 6 sec at the rate of 2 m/s²

Hence

• u = 4 m/s
• a = 2 m/s²
• t = 6 s

Substituting the values

We get

$\sf \longrightarrow v=4+2 \times 6 \ m/s$

$\sf \longrightarrow v=4+12 \ m/s$

Therefore

$\sf \longrightarrow v=16 \ m/s$

Hence

$\checkmark$ Final velocity = 16 m/s

Answer 2

Answer:

16 m/s

Explanation:

$\underline{\bigstar\:\textsf{Given:}}$

• Initial velocity (u) = 4 m/s
• Time (t) = 6 s
• Acceleration (a) = 2 m/s²

$\underline{\bigstar\:\textsf{To\:find:}}$

• Final velocity (v) = ?

$\underline{\bigstar\:\textsf{Solution:}}$

Let's analyze the situation !

A boy is moving by a bike with velocity (u) of 4 m/s it accelerated for 6 seconds at the rate of 2 m/s². Now, we have to find its final velocity (v).

Let's find now !

We remember Newton's 1st law of motion i.e, $\green{\sf{v\:=\:u\:+\:at}}$

$\implies$ v = 4 + 2 × 6

$\implies$ v = 4 + 12

$\implies$ v = 16 m/s

${\large{\boxed{\sf{\therefore \:Final\:velocity\:is\:16\:m/s}}}}$