Question

a boy moving by a bike with the velocity 4 m/ s accelerate for 6 sec . at the rate of 2 m / s . find its final velocity​

Answer 1

$\bigstar$ Given:-

• A boy moving by a bike with the velocity 4 m/s accelerate for 6 sec at the rate of 2 m/s²

$\bigstar$ To Find

• Final velocity

$\bigstar$ Solution

We know that

Equation of motion

$\sf \longrightarrow v=u+at$

Here

v = Final velocity

u = Initial velocity

a = Acceleration

t = Time

Units

• v = m/s
• u = m/s
• a = m/s²
• t = s

According to the question:-

We are asked to find final velocity

Therefore

We must find "v"

Given that

A boy moving by a bike with the velocity 4 m/s accelerate for 6 sec at the rate of 2 m/s²

Hence,

u = 4 m/s

a = 2 m/s²

t = 6 s

Substituting the values:-

We get

$\sf \longrightarrow v=4+2 \times 6 \ m/s$

$\sf \longrightarrow v=4+12 \ m/s$

Therefore

$\sf \longrightarrow v=16 \ m/s$

Hence

$\checkmark$ Final velocity = 16 m/s

Answer 2

A boy moving by a bike with the velocity 4 m/s accelerate for 6 sec at the rate of 2 m/s²

$\bigstar To \: Find$

Final velocity

$\bigstar \: solution$

We know that

Equation of motion

$\sf \longrightarrow v=u+at$

Here

v = Final velocity

u = Initial velocity

a = Acceleration

t = Time

Units

v = m/s

u = m/s

a = m/s²

t = s

According to the question

We are asked to find final velocity

Therefore

We must find "v"

Given that

A boy moving by a bike with the velocity 4 m/s accelerate for 6 sec at the rate of 2 m/s²

Hence

u = 4 m/s

a = 2 m/s²

t = 6 s

Substituting the values

We get

$\sf \longrightarrow v=4+2 \times 6 \ m/s$

$\sf \longrightarrow v=4+12 \ m/s$

Therefore

$\sf \longrightarrow v=16 \ m/s$

Hence

$\checkmark Final \: velocity = 16 m/s$

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