Question

A boy moving with a velocity of 3m/s is brought to rest by a constant force after traveling 15m, Calculate the retardation

Answer 1

Explanation:

initial velocity, u= 3m/s

final velocity, v=0m/s

distance, s = 15m

we know that

from third equation of motion,

v²-u² =2as

substituting the values,

0-9=2×a×15

-9=30a

a= -9/30

a= -0.3m/s²

☆Hence retardation of the boy = 0.3 m/s²

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