Question

A BOY OBSERVED THE TOP OF AN ELECTRIC POLE TO BE AT AN ANGLE OF ELEVATION OF 60° WHEN THE OBSERVATION POINT IS 8 METERS AWAY FROM THE FOOT OF THE POLE. FIND THE HEIGHT OF THE POLE​

Answer 1

Answer:

$8 \sqrt{3} m$

step by step explanation:

given :

Let AB is be the electric pole, angle ABC be the angle of elevation

solution:

teta=60°

BC=8m

tan 60°=AB/BC

root3=AB/8

AB=(8×root3)m

hence, height of the elecyric pole is 8root3 m