Question

A boy of 20kg weight sits at a distance of 1.2m from the fulcrum of a sea-saw. Another boy balances the see-saw on sitting at a distance of 50cm from the fulcrum. Calculate his weight.

Answer 1

Answer:

Solution

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Let, the man weighing 60 kg will be at a distance of x m from the centre of the see-saw.

Using equilibrium of moment of force,

60×g×x=20×g×1.2

x=

60

20×1.2

x=0.4m.

Explanation:

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Answer 2

Explanation:

Torque of both the masses would be equal.

Torque = F x R (perpendicular)

20 x 10 x 1.2 = 50/100 x mass x 10 (F= mg, g = 10)

mass = 48kg