Question

a boy of 5kg force applied 20N and displace 10m along same direction and in opposite 5N force is applied find
each work done and also find net work done .​

Answer 1

Explanation:

WORK=F.s

FOR 20N

W=20×10

W=200 J

FOR 5N

W=5×10

=50 J

NET WORK

=W=(F1-F2)×S

=W=(20-5)×10

W=150 N