A boy of height 1.75m is walking away from the base of a lamp post at a speed of 1.2m/s . If the lamp is 7m above the ground , then find the lenght of the shadow after 5sec.!!!!!! plz guys tell
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just change the value method is like this
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J0hn01:
thanku
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BC=1.2*5=6 m
angle D= angle D (COMMON)
angle B=angle C =90
AB/EC=BD/CD
7/1.75=x+6/x
700/175=x+6/x
4=x+6/x
4x=x+6
4x-x=6
3x=6
x=6/3
x=2 m
length of her shadow is 2 m
PLEAS MARK AS BRAINLIEST!!!!!!!!!
angle D= angle D (COMMON)
angle B=angle C =90
AB/EC=BD/CD
7/1.75=x+6/x
700/175=x+6/x
4=x+6/x
4x=x+6
4x-x=6
3x=6
x=6/3
x=2 m
length of her shadow is 2 m
PLEAS MARK AS BRAINLIEST!!!!!!!!!
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