A boy of height 120cm is walking away from base of lamp post is 4.8m above ground.Then find the length of his shadow after 5 seconds
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Speed of boy relative to post in a second=6m/s
In 5 sec distance covered by boy=30m
Now
By triangle property
AB/BC=DE/EC
AB is length of post
BC distance between lamp a d boy's shadow
DE is boys height
EC is his shadow
Let it be x
4.8/30+x=1.2/x
Solving x=10m
In 5 sec distance covered by boy=30m
Now
By triangle property
AB/BC=DE/EC
AB is length of post
BC distance between lamp a d boy's shadow
DE is boys height
EC is his shadow
Let it be x
4.8/30+x=1.2/x
Solving x=10m
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