a boy of height 150cm east a shadow of 2mt when standing at a distance of 8m from a tower
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In ∆ABE and ∆CDE
angle B=angle D
angle E=angle E
therefore , ∆ABE~∆CDE
AB/CD=BE/DE
AB/1.5=10/2
AB/1.5=5
AB=1.5×5
AB=7.5
therefore length of tower=7.5m
angle B=angle D
angle E=angle E
therefore , ∆ABE~∆CDE
AB/CD=BE/DE
AB/1.5=10/2
AB/1.5=5
AB=1.5×5
AB=7.5
therefore length of tower=7.5m
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