Question

A boy of mass 10kg is standing on a 4 kg block as shown.The whole system is on smooth level ground. The boy jumps to the right with a velocity of 7m/s relative to the 4 kg block.Find the maximum velocity of 1kg block (in m/sec ) in the subsequent motion. ​

Answer 1

Answer:

Explanation:

Answer:

Dear Student,

Answer 2

Answer: The maximum velocity is 8 m/s.

Explanation:

For a 4 kg block let the velocity be v m/s.

hence, 4(-v - 0) + 10 (7 - v) =0.

v = 5 m/s.

At the time of maximum compression v1 = v2.

hence

v1 + 4v2 = 20

and v1² + 4v2² =100.

Comparing both the equations we get v1= 8 m/s.