Question

A boy of mass 40 kg is running at 1 m/s inside his classroom, which is on the second floor of his school. If each floor is 12 m above the one below it, find his:
a. Kinetic energy b. Potential energy

Answer 1

Explanation:

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Answer 2

Answer:

a. Kinetic energy-20J

b. Potential energy-960J

Explanation:

From the question we have the following data:

The mass of the boy(m)=40kg

The speed with which the boy is running(v)=1m/s

Distance between two consecutive floors=12m

The boy is on the second floor of his school.

Kinetic Energy(K.E.)

$K.E.=\frac{1}{2}mv^2$    (1)

Inserting the entities in equation (1) we get;

$K.E.=\frac{1}{2}\times 40\times 1^2$

$K.E.=20\ J$     (2)

Potential Energy(P.E.)

$P.E.=mgh$       (3)

g=acceleration de to gravity=10m/s²

h=height at which the body is present=24m

Placing values in equation (3) we get;

$P.E.=40\times 10\times 24$

$P.E.=960\ J$       (4)

So, the kinetic energy and potential energy of the boy are 20J and 960J respectively.

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