Question

A boy of mass 40 kg jumps out of a boat of 200 kg on the bank, with a velocity of 2m/ s. If the momentum is conserved. With what velocity the boat will move backwards?​

Answer 1

Answer:

Correct option is

B

−120kg.ms−1

Using momentum conservation,

m1u1+m2u2=m1v1+m2v2

m1=mass of boy   m2=mass  of  boat

m1=40kg ,v1=3 m/s      u1=0 u2=0

⇒40×0+m2×0=40×3+m2×v2

⇒0+0=120+Pboat

0=Pboat+120

Pboat=−120 kgm/s

Explanation:

plz mark me as brainlist bro