Question

. A boy of mass 40 kg jumps with a horizontal velocity of 5 ms-1 onto a stationary cart with frictionless wheels. The mass of the cart is 3 kg. What is his velocity as the cart starts moving? Assume that there is no external unbalanced force working in horizontal direction​

Answer 1

Answer:

V= 200/43 m/s

Explanation:

Given : M

girl

=40 kg u

girl

=5 m/s M

cart

=3 kg

Initial velocity of cart u

cart

=0

Let the final velocity of cart be V.

Applying conservation of linear momentum : P

i

=P

f

Or M

girl

u

girl

+M

cart

u

cart

=(M

girl

+M

cart

)V

Or 40×5+3×0=(40+3)V

⟹ V=

43

200 m/s