Question

a boy of mass 40 kg running at 2 m/s jumps on to a 10 kg trolley traveling in the same direction at 1 m/s what is the common velocity?​

Answer 1

Explanation:

$\huge \star\sf \green{Answer} \huge \star$

$\tt \orange{Given}$

☞m1= 50kg

v1 = 5m/s

☞m2 = 20kg

v2 = 1.5m/s

$\tt \pink{After \: jump}$

☞total mass(M)= 50+20 = 70kg

final velocity= v

☞according to conservation of momentum

Mv = m1v1 + m2v2

70×v = 50×5 + 20×1.5

70v = 280

v = 280/70

v = 4m/s

☞Their common velocity will be 4 m/s

Answer 2

Explanation:

\huge \star\sf \green{Answer} \huge \star⋆Answer⋆

\tt \orange{Given}Given

☞m1= 50kg

v1 = 5m/s

☞m2 = 20kg

v2 = 1.5m/s

\tt \pink{After \: jump}Afterjump

☞total mass(M)= 50+20 = 70kg

final velocity= v

☞according to conservation of momentum

Mv = m1v1 + m2v2

70×v = 50×5 + 20×1.5

70v = 280

v = 280/70

v = 4m/s

☞Their common velocity will be 4 m/s