Question

A boy of mass 40 kg wants to climb up a rope hanging vertically the rock and b stand a maximum tension of 500 newton what is the maximum acceleration with which the boy can climb the rope

Answer 1

500÷40=12.5 is answer

Answer 2

The maximum acceleration with which the boy can climb the rope is 2.5 m/s²

A boy of mass 40 kg wants to climb up a rope hanging vertically the rock which stands a maximum tension of 500 newton.

We have to find the maximum acceleration with which the boy can climb the rope.

See the free body diagram of boy with maximum acceleration a.

• Since boy is climbing with an acceleration, a psuedo force, F = ma , acting just downward direction to apply Newton's law.
• The boy can climb the rope, when the tension acting on the string is able to balance net force acting by boy with maximum force. i.e., Tension = weight of boy + psuedo force

here, Tension = 500 N,

weight of boy = mg = 40 kg × 10 m/s² = 400N

psuedo force = ma = 40kg × a = 40a

∴ 500 = 400 + 40a

⇒ a = 100/40 = 2.5 m/s²

Therefore the maximum acceleration of boy is 2.5 m/s².