Question

a boy of mass 40 kg wants to climb up a rope hanging vertically.the rope can with stand a maximum tension of 600 N.the maximum acceleration with which of the boy can climb the rope​

Answer 1

Given

• Mass = 40 kg
• T_max = 600 N

To Find

• Maximum acceleration

Solution

☯ F = ma

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✭ According to the Question :

⇒ F = ma

• If we draw a FBD, we'll know that,

⇒ F = T - mg

⇒ T - mg = ma

⇒ T = ma + mg

⇒ T = m(a+g)

⇒ 600 = 40(a+10)

• (Considering g = 10 m/s²)

⇒ 600/40 = a + 10

⇒ 15 = a + 10

⇒ a = 5 m/s²

∴ The maximum acceleration is equal to 5 m/s²

Answer 2

QUESTION :-

• a boy of mass 40 kg wants to climb up a rope hanging vertically.the rope can with stand a maximum tension of 600 N.the maximum acceleration with which of the boy can climb the rope

GIVEN :-

• a boy of mass 40 kg
• stand a maximum tension of 600 N

TO FIND :-

• we have to find maximum Acceleration = ?

SOLUTION :-

• T max = 600 N

• L et be the acceleration with which the
• body can climb the rope

• T max - mg = ma

substituting the value in above equation we get :-

• 600 = 40 × ( 10 + a)

• 10 + a = 600/40 = 15 m/s

• = 15 - 10 = 5 m/s²

maximum acceleration with which of the boy can

climb the rope = 5 m/s²

ADDITIONAL INFORMATION :-

• important role in the above solution is
• tension, which can be explained as the forcethat is transmitted through a rope, string, or wire when pulled by forces acting from opposite sides. At the ends, the tension force is directed over the wire's length and pulls energy equally on the bodies.