Question

A boy of mass 45 kg jumps with a horizontal velocity of U m/s onto a stationary cart with frictionless wheels. The mass of the cart is 5 kg. Assume, no external unbalanced force working in the horizontal direction. Find
U , if cart starts moving with velocity of 4.5 m/s? solve step by step

Answer 1

Answer:

$Mgirl=40 kg           ugirl=5 m/s        Mcart=3 kg$

$ucart=0$

$initial \: velocity \: will \: be \: V$

$linear \: momentum \: = Pi=Pf</p><p>$

$Mgirl \: ugirl+Mcart \: ucart=(Mgirl+Mcart)V$

$40×5+3×0=(40+3)V$

$v = \frac{200}{43} \: m \: s$

Answer 2

Answer:

$⇝ucart=0ucart=0$

$⇝initial \: velocity \: will \: be \: VinitialvelocitywillbeV$

$⇝linear \: momentum \: =Pi=Pflinearmomentum=Pi=Pf$

$⇝Mgirl \: ugirl+Mcart \: ucart=(Mgirl+Mcart)VMgirlugirl+Mcartucart=(Mgirl+Mcart)V$

$⇝40×5+3×0=(40+3)V40×5+3×0=(40+3)V$

$⇝v = \frac{200}{43} \: m \: sv= 43 /200ms\:=\:4.65116279$