A boy of mass 45 kg stands on a square wooden block of 50 CM side. Calculate the pressure exerted by the boy on the block.
Answers
Answered by
70
HEY BUDDY..!!!!
HERE'S THE ANSWER..
_______________________________
♠️ We know Pressure is force per unit are , i.e
✔️ P = F / A
⏺️P = pressure = ?
⏺️F ( force ) = mass × Acceleration ( g )
⏺️A is area on which force is acting
✔️ A = side × side = 0.5 m × 0.5 m = { 0.25 m^2 }
✔️ F = mass × g
=> Force = 45 × 10 // g = 10 m / s^2
=> Force = 450 Newton ( N )
♠️ Now finding pressure
=> Pressure = Force / Area
=> P = 450 / 0.25
=> [ P = 1800 Kg / m^2 or 1800 Pascal ( Pa ) ] ✔️✔️
♠️ Pressure exerted by boy on box is 1800 Pa
HOPE IT HELPS..
JAI HIND..
:-)
HERE'S THE ANSWER..
_______________________________
♠️ We know Pressure is force per unit are , i.e
✔️ P = F / A
⏺️P = pressure = ?
⏺️F ( force ) = mass × Acceleration ( g )
⏺️A is area on which force is acting
✔️ A = side × side = 0.5 m × 0.5 m = { 0.25 m^2 }
✔️ F = mass × g
=> Force = 45 × 10 // g = 10 m / s^2
=> Force = 450 Newton ( N )
♠️ Now finding pressure
=> Pressure = Force / Area
=> P = 450 / 0.25
=> [ P = 1800 Kg / m^2 or 1800 Pascal ( Pa ) ] ✔️✔️
♠️ Pressure exerted by boy on box is 1800 Pa
HOPE IT HELPS..
JAI HIND..
:-)
hdkshsbs:
awsm
Answered by
45
P = f / a
f = m.g
f = 10 × 45
f = 450 N
a = 0.5 × 0.5
a = 0.25
p = f / a
p = 450 / 0.25
p = 1800 Pa
f = m.g
f = 10 × 45
f = 450 N
a = 0.5 × 0.5
a = 0.25
p = f / a
p = 450 / 0.25
p = 1800 Pa
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