Question

A boy of mass 45kg stands on a square wooden block of50cm side . Calculate the pressure exerted by the boy on the block

Answer 1

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Answer 2

Since, In this question,

Given that,

Mass of Boy(m) = 45 kg

Side of Square (a) = 50 cm

Now,

Pressure = Thurst/Area

So, at first we will find Thurst i.e.

F = mg
=> F = 45 x 10 = 450 N
Side of Square = 50 cm = 0.5 m

Area of Square = a^2 = (0.5 x 0.5) m^2 = 0.25 m^2

Now, As per Formula,

$= > p \: = \frac{f}{a}$

$= > p \: = \frac{450}{0.25} \: pa$

$= > \: p \: = 1800 \: pa$


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