Question

A boy of mass 50 kg jumps to a height of 1.6 m. What's his potential energy and kinetic energy at the highest point?

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Answer 1

A boy of mass 50 kg jumps to a height of 1.6 m.

Here..

mass (m) = 50 kg

height (h) = 1.6 m

acceleration (a) = 10 m/s²

$\boxed{\boxed{Potential\: Energy \:(P.E)\:= \:mgh}}$

= 50 × 1.6 × 10

$\textbf{P.E = 800 J}$

$\boxed{\boxed{Kinetic\:Energy\:(K.E)\:=\:\dfrac{1}{2}\:\times\:m{v}^{2}}}$

[At highest point initial velocity (u) & final velocity (v) becomes zero]

So..

mass (m) = 50 kg

final velocity (v) = 0 m/s

acceleration (a) = 10 m/s²

K.E = $\dfrac{1}{2}$ × 50 × (0)²

$\textbf{K.E = 0 J}$