A boy of mass 50 kg running at 5 metre per second jumps on a 20 kg trolley travelling in the same direction at 1.5 m per second. what is there common velocity?? please answer me fast.....
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m1u1+m2u2v=(m1+m2)v=m1u1+m2u2m1+m2=50⋅5+20⋅1.550+20=4 m/sm1u1+m2u2=(m1+m2)vv=m1u1+m2u2m1+m2=50⋅5+20⋅1.550+20=4 m/s
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Mass of boy = m1 = 50 kg
Mass of trolley = m2 = 20 kg
Initial velocity of boy = u1 = 5 ms-1
Initial velocity of trolley = u2 = 1.5 ms-1
Final velocity =
v = m1u1 + m2u2 \ m1 + m2
50 × 5 + 20 × 1.5 ÷ 50 + 20
= 4ms-1
HOPE IT HELPS YOU!!!
Mass of trolley = m2 = 20 kg
Initial velocity of boy = u1 = 5 ms-1
Initial velocity of trolley = u2 = 1.5 ms-1
Final velocity =
v = m1u1 + m2u2 \ m1 + m2
50 × 5 + 20 × 1.5 ÷ 50 + 20
= 4ms-1
HOPE IT HELPS YOU!!!
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