A boy of mass 50kg is standing on a weighing machine placed on the floor of a lift. the machine reads his weight in n. what is the reading of the machine if the lift is moving upwards with a uniform speed of 10m/s?
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Answer:
490 N
Mass of the boy,
m
=
50
k
g
Acceleration due to gravity,
g
=
9.8
m
s
−
2
Let the weighing machine exert a normal force N on the boy in vertically upward direction.
As the lift is stationary, acceleration of the boy is zero.
From second law of motion,
N
−
m
g
=
0
⇒
N
=
m
g
=
50
]×
9.8=490
N
The machine measures this normal force.
Explanation:
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